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3x^2-7x-68=0
a = 3; b = -7; c = -68;
Δ = b2-4ac
Δ = -72-4·3·(-68)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{865}}{2*3}=\frac{7-\sqrt{865}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{865}}{2*3}=\frac{7+\sqrt{865}}{6} $
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